Question Pool Effects of Electric Current

# Effects of Electric Current - SAMAGRA Question Pool & Answers | Class 10 English Medium

Kerala Syllabus SAMAGRA SCERT SAMAGRA Question Pool for Class 10 English Medium Physics Effects of Electric Current

Qn 1. It is said that a fuse wire of proper amperage should be used in an electrical circuit . why
If amperage of fuse wire is more than correct value, the circuit does not break even excess current flows through circuit. If amperage of fusewire is less, the circuit

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Qn 2. An electric heater of resistance 230? is connected to 230V supply. Calculate the heat energy produced by it in 1 second.
H = V2/R x t = (230 x230 / 230 ) x 1 = 230

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Qn 3. Analyse the given circuit diagram and answer the following questions. 1. What will be the electric current through the resistance A ? 2. What will be the electric current through the resistance B ? 3. What will be the ammeter reading? 4. How should be the resistance wire be arranged to reduce the ammeter reading ?
1. Current through A, I1 = V/R = 12/3 = 4A 2. Current through B, I2 = V/R = 12/6 = 2A 3.Ammeter Reading = I1 + I2 = 4 +

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Qn 4. Nichrome is not used as filament in filament lamps. Why ?
Nichrome can only remain red hot and does not produce white light while heating

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Qn 5. Ajith says that if we use tungsten as heating coil we will get light energy as well as heat energy. What is your response to his statement ?
Tungsten cannot be used as heating coil because it gets oxidized while

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Qn 6.

A filament Lamp designed to work at a potential difference 250V has power 100W. What will be the power of this lamp when connected to a 100V supply?

We know ,power P = V2/R

R = V2/P = 250 x 250 /100 = 625 W

When connected to 100 V power supply ,

Power P =

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Qn 7.

A heating coil of 10000? resistance works in 250V supply.

1. What is the current flowing in it ?
2. What is the power of heater ?
3. Will there be any difference in the temperature, If we reduce the length of the heating coil ? Why?
1. I = V/R = 250/1000 = .25 A
2. P = V2 /R =250 x250 /1000 = 62.5 W
3. Yes, The resistance decreases when

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Qn 8.

Nowadays LED Lamps are widely used .

1. Name any two parts of this lamp & write the working of it.
2. Name any two instruments/tools used in the making of LED Lamp.
1. LED Chip board - LED is connected Heat sink- to absorb heat Power supply Board-Provides required DC to LED Diffuser cup

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Qn 9.

A,B,C,D & E are five 10Ω resistors connected in a circuit as in the given diagram.

1. Calculate the effective resistance of the circuit.
2. What is the electric current through the circuit.

1) Effective resistance of A and B,  R1 =A+B=10+10=20 ohm

Effective resistance of c and D,  R2 = C + D= 10 +10 = 20 ohm

Effective resistance

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Qn 10.

Resistance of a 20cm long conductor is 20?. The conductor is bent into circular loops and connected in the circuit as in the given diagrams, Calculate the resultant resistance in each case.

Fig (i) Effective resistance = 20 Ohms Fig(ii) two 10Resistances are connected as parallel so Effective resistance, 1/R = 1/R1 + 1/R2 =

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Qn 11.

Power of a bulb which works in 220V is 100W. When the voltage in the circuit decreases the power becomes 25W, What will be the voltage at that time?

P = V2/R

R = V2/P = 220 x 220 /100 = 484 Ω

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Qn 12.

Match the following related to LED Lamp

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Qn 13.

LED Lamps save energy & are ecofriendly. Justify this statement

• As there is no filament, there is no loss of energy in the form
of

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Qn 14.

Calculate the amount of heat energy produced when 1A current flows through a 1? resistance wire for 1 hour.

Given That,

Resistance, R= 1?

Current,I=1 A

Time, t=1 hour=3600

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Qn 15.
• Calculate the highest resistance that can be made  by using five 1Ω resistors ?
• What is the lowest resistance  made by the same five 1Ω resistors. ?
• Draw a circuit in which these resistance are arranged inorder to get the effective resistance = 3 1/2 Ω

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Qn 16.

• Calculate the effective resistance in the above circuit
• If the electric current is flowing for 10minutes, calculate the amount of heat energy produced?
• Calculate the heat energy produced in 10 minutes if these resistors are connected in parallel.

• R=R1+R2 =4+2=6 Ω
• H =V2 /Rt = (12 x 12 /6 )x 10 x 60=14400 J
• Effective Resistance, R =

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Qn 17.

An electrical device of power 440W  is connected to  230V power supply. Which among the following is the amperage of fuse to be used in this circuit ?

(a) 0.5A  (b) 2A  (c) 1.5A  (d) 4A

Amperage = wattage/voltage

=440/230

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Qn 18.

1. When the switch is on, calculate the current in the circuit.
2. What is the purpose of fuse in a circuit ?
3. What is the amperage of the fuse wire that can be used in this circuit?
1. P= V I →  I=P/V= 100/230 = 0.434
2. Fuse melts during Short circuit and

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Qn 19.

The given experiment is based on heating effect of electric current

1. Which device is used  to change the intensity of current in the circuit
2. Nichrome  is used to make the heating coil to change the temperature of water.Why do we use this  material as heating element?
3. If we double the length of the coil immersed in water, what will be the change in the heat energy produced ?
1. Rheostat
2. Nichrome has high resistivity and high melting point
3. When the length doubles the current decreases to half. So heat also decreases

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Qn 20.
1. Name any to electrical heating devices.
2. Name the constituent metal  in the alloy used to make the heating coil of a heating appliance.
3. Calculate the heat energy produced when 1A current flows through 100Ω resistance wire for 1hour.

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Qn 21.

Aluminium and Nichrome wires of same length and thickness are used in the given circuit.

1. In which circuit the current through Aluminium and Nichrome  are  the same?
2. In which circuit, Nichrome wire gets heated more. Explain.
1. a
2. b

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Qn 22.

Analyse the diagram and answer the following questions.

1. How is Rheostat and resistor connected in this circuit?
2. If the Rheostat offers a Resistance of 50Ω, what is the current in the circuit

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Qn 23.

If a bulb  labelled as 100W/230V is connected to 115V power supply, What will be its Power ?                                                                                                                  (100W,25W, 12.5W, 50W)

P=  25W

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Qn 24.

Observe the given circuit Diagram. B1 is a torch bulb and B2 is an ordinary incandescent bulb.

1. Among B1  and B2 Which which one have higher resistance ?
2. If we switch on the circuit as arranged in diagram, Whether both the the bulbs will glow or not glow
3. What happens if we switch on the circuit after replacing B2 with another B1. Explain

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Qn 25.
1. Write two disadvantages of incandescent lamps?
2. What is the arrangement/facility provided to increase the life of such bulbs.
3. How does the oxidation of filament reduced in such lamps?
• A portion of electric energy is loses as

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Qn 26.

When excess electric current flows through the circuit, fuse wire melts & breaks the circuit.

1. Whether heat energy is produced when allowed amount of current flows in the circuit ? If yes why does not the fuse wire break?
2. Why does fuse wire melt when excess electric current flows through the circuit
1. Yes, heat is produced.When current is flowing through the fuse wire small quantity of heat is producing but that heat is

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Qn 27.

Find the relation in the first then complete the second pair

1.  Bulb : Light effect                                                                                                           Safety Fuse : ..................
2. Nichrome : High Melting Point                                                                                Fuse wire: ...................
1. Heating Effect
2. Low melting

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Qn 28.

Heat energy produced in a current carrying conductor is equal to the product of square of current through the conductor, Resistance of the conductor and the time for which the current flows.

1. Which law is stated above?
2.  If we increase the current 10 times, what will be the increase in the heat energy produced ?
3. If double the resistance of the conductor what will be the change in the heat energy produced ?

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Qn 29.

Find the relation and complete the following:                                                    Electrical energy Heat energy → Heating effect → Electric Stove                          Electrical energy →Chemical energy → Chemical effect → .....................

Storage Battery

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Qn 30.

A and B are two electrical devices,

 Device A Device B 230V 230V 1000W 50W
1. If both the devices are working for the same time which among  will produce more electrical Energy ?

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Qn 31.

Find the correct answer from the following:                                                                   The device works on the heating effect of electric current.

1. Fan
2. LED
3. Fuse
4. CFL

Fuse

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Qn 32.

240V power supply  is maintained in household circuits.

1. Find the resistance of heating coil of an electric iron if 2A current is flowing through it.
2. How much electrical energy is consumed when this device works for 5 minutes?

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Qn 33.

Match suitably:

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Qn 34.

The cautionary measures are given while the fuse wire is included in the circuit.

1. Fuse wire should not extend out of the carrier base.
2. Edges of the fuse wire should be fixed firmly.
3. Fuse wire should be connected in parallel to the circuit.
1. Which statement among the above is correct ?
2. Rewrite the wrong statement after necessary corrections
1. a and b
2. Fuse should connect in series with the

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Qn 35.

In an electric heater 800W , 400V  is labelled.

1. What does it mean?
2. If it is working in 200V power supply  calculate the current through the device.Find the power in this situation?

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