Kerala Syllabus SAMAGRA SCERT SAMAGRA Question Pool for Class 9 English Medium Maths Area

PQ = 7 cm, QR = 6cm, ∠Q=40. Then
a) Draw the triangle PQR.
b) Draw a triangle with the same area and with one side PR.
a) For drawing triangle PQR
b)For
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In the figure ABCD is a rectangle and ABTU is a parallelogram. Then
a) If area of triangle ABU is k then what is the area of the parallelogram
b) Prove that DU = CT
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In triangle ABC, AB=6 cm, ∠A=55˚, ∠B=60˚. Draw triangle ABC. Draw an isosceles triangle with the same area.
For drawing triangle ABC
Drawing an isosceles triangle with the same
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Area of the rectangle PQRS is 120 sq. cm. What is the area of the parallelogram PQTR, why?
Area ofPQRS = 120 sq.cm.
Area of triangle PQR = 60
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a) What is the measure of ∠SPT.
b) What is the breadth of rectangle PQRS.
c) Find the area of the rectangle
d) What is the area of each triangles?
a) ∠SPT = 450
b) PS = ST = 4
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In triangle ABC, AB = 6 cm, BC = 7cm, ∠B=30 . Then
a) Draw the triangle ABC.
b) Draw a right angled triangle having same area.
c) Measure the perpendicular sides
d) Find the area of the triangles
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In triangle ABC, AB = 5 cm, BC = 6cm, AC=7 cm. Draw the triangle. Then draw another triangle having the same area.
For drawing triangle ABC
Drawing a line parellel to one
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In the figure ABCD is a rectangle AB=12 m and BC = 8 m. Then
Find the area of the shaded portion.
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In the figure ABCD is a rectangle AB=8 cm and BC = 6 cm. Then
a) What is the area of the rectangle ABCD?
b) What is the area of the rectangle APQC? Why?
c) Find the length of AP
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In the figure ABCD is a rectangle AB=10 cm and BC = 6 cm. Then
a) What is the area of the rectangle?
b) What is the area of the triangle APB?
a) 10 x 6 = 60
b) 60/2 =
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