Kerala Syllabus SAMAGRA SCERT SAMAGRA Question Pool for Class 9 English Medium Maths Area
PQ = 7 cm, QR = 6cm, ∠Q=40. Then
a) Draw the triangle PQR.
b) Draw a triangle with the same area and with one side PR.
a) For drawing triangle PQR
b)For
In the figure ABCD is a rectangle and ABTU is a parallelogram. Then
a) If area of triangle ABU is k then what is the area of the parallelogram
b) Prove that DU = CT
In triangle ABC, AB=6 cm, ∠A=55˚, ∠B=60˚. Draw triangle ABC. Draw an isosceles triangle with the same area.
For drawing triangle ABC
Drawing an isosceles triangle with the same
Area of the rectangle PQRS is 120 sq. cm. What is the area of the parallelogram PQTR, why?
Area ofPQRS = 120 sq.cm.
Area of triangle PQR = 60
a) What is the measure of ∠SPT.
b) What is the breadth of rectangle PQRS.
c) Find the area of the rectangle
d) What is the area of each triangles?
a) ∠SPT = 450
b) PS = ST = 4
In triangle ABC, AB = 6 cm, BC = 7cm, ∠B=30 . Then
a) Draw the triangle ABC.
b) Draw a right angled triangle having same area.
c) Measure the perpendicular sides
d) Find the area of the triangles
In triangle ABC, AB = 5 cm, BC = 6cm, AC=7 cm. Draw the triangle. Then draw another triangle having the same area.
For drawing triangle ABC
Drawing a line parellel to one
In the figure ABCD is a rectangle AB=12 m and BC = 8 m. Then
Find the area of the shaded portion.
In the figure ABCD is a rectangle AB=8 cm and BC = 6 cm. Then
a) What is the area of the rectangle ABCD?
b) What is the area of the rectangle APQC? Why?
c) Find the length of AP
In the figure ABCD is a rectangle AB=10 cm and BC = 6 cm. Then
a) What is the area of the rectangle?
b) What is the area of the triangle APB?
a) 10 x 6 = 60
b) 60/2 =