Question Pool Circle Measures

# Circle Measures - SAMAGRA Question Pool & Answers | Class 9 English Medium

Kerala Syllabus SAMAGRA SCERT SAMAGRA Question Pool for Class 9 English Medium Maths Circle Measures Qn 1.

How much more is the perimeter of a circle of radius 15 centimetre than the perimeter of radius 5 centimetre ?

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Qn 2. In the figure all the vertices of the equilateral triangle are on a circle. If one side of the triangle is 10√3 cm

(a) Write the measures of angles of triangle OAP

(b) Find the radius of the circle

(c) Find the perimeter of the circle

(d) Calculate the area of the circle

(a) 30° , 60° , 90°

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Qn 3.

If the perimeter of a circle is 20 π find its area?

2 πr = 20 π

r = 10 cm

Areab = π x 10 x 10 = 100π

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Qn 4. If a circle is drawn through all the vertices of a regular hexagon of side 6 centimetre, then

(a) Find the radius of the circle

(b) Find the perimeter of the circle.

(a)   radius of the circle = 8

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Qn 5. A circle is drawn inside a square of side 6 cm. as shown in the figure.

a) What is the radius of the circle ?

b) Find the area of the shaded portion.

a) Radius of the circle  = 3 സെ.മീ.

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Qn 6.

A circle is made using an arc of central angle 120° which is cut from a circle of radius 12 cm.

(a) What is the length of the arc ?

(b) What is the perimeter of the new circle ?

(c) Find the area of the new circle

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Qn 7. If the side of a square is 8 cm and its four vertices are on a circle , then

(a) What is the area of the square ?

(b) Find the diagonal of the square?

(c) Find the area of the shaded portion in the figure.

Area of the square = 64 sq.cm .

diagonal length of the

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Qn 8. A sector is drawn by taking one vertex of a square having side 8 cm as centre. Find the area of the sector.

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Qn 9.

If the radius of a circle is 10 cm , what will be the arc length of a sector having central angle 60° ?

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Qn 10.

If the central angle of a sector with arc length 12π is 120° , then

a) What is the perimeter of the circle ?

b) What is the radius of the circle ?

a) Perimetere = 3 x 12π = 36 π

b) Radius= 36 π / 2π =