Kerala Syllabus SAMAGRA SCERT SAMAGRA Question Pool for Class 10 English Medium Maths Circles
A,B, C are points in the circle with centre O. If ∠OCA = x then
Prove that ∠OCA + ∠ABC = 90°
In the circle with centre O , ∠ CAD= 40° then
Find ∠B, and ∠ACD?
∠B = ∠D= 90°
In the figure O is the centre of the circle. And ∠ADB=120° ,∠OAC=30° , Then
Justify that ABC is an equilateral Triangle.
In the figure ∠C= 40°,∠OBC=15°
Find all angles of triangle ABC
Draw a rectangle of length 6cm and breadth 4cm
Construct a square having same area of the rectangle.
In the figure PA=PC, Which are the triangles formed when AC and BD are joined ?
Prove that ABDC is an isosceles trapezium?
a) ?PAC, ?PBD
In the figure if we draw a circle with diagonal BD of the quadrilateral ABCD as diameter , where will be the positions of the vertices A and C (∠ C = )?
A is on the circle and C is in the
Draw a circle with radius 3 cm .Construct a triangle with vertices on the circle and having angles 50° , 60° , 70°
In the figure the chords MA and NB extended and met at P. MA=5cm , PA=7cm and PB=6cm.Calculate the length of NB?
PA xPM= PB xPN
a) What is the measure of ∠ADC ?
b) Find the radius of the circle.
b) diameter = 10 cm
radius = 5cm
In the figure ?ABC is equilateral. BD=CD, AC=12cm and CD=5cm.Then
Find the measure of ACB
Find the measure of D
Find the measure of BCD
Calculate the diameter of the circle
a) ∠ACB =60°
b) ∠D =120°
In the figure O is the centre of the circle. If ∠AOC=100°
find ∠ABC ?
In the figure ∠BAC = 35° find the measures of ∠BDC and ∠ADC?
∠BDC = 35°
∠ADC = ∠ADB + ∠BDC = 90 + 35 =
In the figure O is the centre of the circle. If ∠ AOB = 80° Find the measures of ∠ OCB and ∠ OBC
In the figure of a clock , numbers 12 , 7 , and 5 are joined to form a triangle.
(a) What are the measure of the angles of this triangle ?
(b) Give a suitable name for this triangle.
(c) Howmany such triangles can be drawn in this clock ?
In the figure the length of the arc CNB is of the perimetre of the circle and the length of the arc AMD is of the perimetre of the circle.
(a) What is the measure of centre angle of the arc CNB ?
(b) Find the measure of ∠ CDB ?
(c) Find the measurement of ∠ ABD.
(d) Write the measurement of ∠ APD.
In the figure chords CE , GD , CF are extended to meet outside the circle at A and B. The lengths AG and BD are equal.
If AE x AC = AG x AD
(a) Write the product equal to BF x BC?
(b) Prove that AE x AC = BF x BC
In the figure O is the centre of the circle and ED is its diametre.
If ∠EGP = 67°
(a) What is the measure of ∠ EDP.
(b) Find other two angles of Δ ODP ?
a) ∠ EDP= 67°
b) ∠ DOP = 46° , ∠ OPD =
Based on the figure find the angles from Part 2 which is equal to the angles in Part 1
|Part 1||Part 2|
∠ACB = ∠ADB
∠ABD = ∠ACD
In the figure O is the centre of the circle and AB is the diametre. If ∠BOC = 120° , Find ∠ OCA and ∠ OAC ?
∠ OCA = ∠ OAC = 60°
In the figure O is the centre of the circle. ?ABC is equilateral
Find the measures of
In the figure PC=10 cm,CD=4cm, and PB:PA=2:3. Then
a) Find the length of PD
b) Find the length of AB
In the circle the chords AB and CD intersect at E. The central angle of arc BQC is 130°. The central angle of arc APD is 40° . Find
a) ∠ACE = 20°
b) ∠CAE = 65°
Based on the figure write the angles from ? BPD equal to the following angles in ? APC
a) ∠ACP = ∠PBD
In the figure PA=9cm, PB=4cm, and PC is 9cm more than PD
(a) If PD = x find the length of PC ?
(b) Find the length of PD ?
(a) PD=x , PC= x+9
(b) PA x PB = PC x PD
9 x 4 = ( x + 9 )x
In the figure O is the centre of the circle and PQ is its diametre.
If PR = OR
(a) Prove that Δ OPR is an equilateral triangle.
(b) Find all the angles of Δ OQR.
In the figure ABCD is a quadrilateral .If a circle is drawn through A,B,and D state the position of the point C as Outside the circle,Inside the circle,or On the circle? Justify your answer.
∠A + ∠C < 180
C is outside the
In the figure ∠ AED=40° then
Which of the following can be the measure of ∠ABC?
(140°, 130° , 150°, 180°)
Using the above measure of ∠ABC , find the measures of angels of ?EAD
∠ ABC=130° ( ∠ABC + ∠E < 180)
∠ EDA=130° ,<EAD
In the figure AB is the diameter of the semicircle. IF AB = 9 cm, PB = 3 cm then
a) find PA ?
b) find PC² ?
c) Draw a square of area 18cm²?
a) PA = 6 cm
b) PC² = PA x PB = 6 x 3 = 18
In the figure P,Q,R,S are points on a circle. Find all angles of quadrilateral PQRS?
∠PSR = 105°
∠ SPQ =85°
Draw the figure in your paper.
(a) Mark a point C on the circle with ∠ MBC = 30°
(b) Join M , B , C to get a triangle .
(c) Find other two angles of the triangle MBC
(d) Write the ratio of the smallest side to the radius of this triangle.
In the figure O is the centre and AB is the diametre of the circle. PC is perpendicular to AB. If
(a) What is the length of OP ?
(b) Find the length of PC .
(c) Write the ratio of the areas of Δ PBC and Δ APC ?
(d) Find the area of quadrilateral ACBD.
(a) OP = 2cm.
(b) PC = √32
(c) For finding the ratio as 1 : 2
A, B, and C are points on the circle with centre O . If ∠A = 60° , BC = 4cm then
(1) Find the circumradius
(2) When ∠A = 30°, Prove that BC is equal to circumradius.
In the figure the diameter of the larger semi circle is 13 cm AP=8cm, PQ = 4 cm.
(a) Then PA x PB =.............
(b) PB = ....................
(c) Find the radius of the smaller semicircle?
(d) What is the area of the square BMRS?
(a) PA xPB=PQ² = 16
(c) Radius of the small semicircle =5 cm